A (–2, 0) and B(2, 0) are two fixed points and P is a point such that PA – PB = 2. Let S be the circle x 2 + y 2 = r 2 Column - IColumn - II(i) If r = 2, then number of points P satisfying to PA – PB = 2 and lying on the circle S is[A] 2(ii) If r =1, then number of point P satisfying to circle S and PA – PB = 2 is[B] 4(iii) For r = 2, the number of common tangents is[C] 0(iv) For r = , the number of common tangents is[D] 1

A (–2, 0) and B(2, 0) are two fixed points and P is a point…

Maths Circle and System of Circles Mix Matrix Match Questions

Published on: August 14, 2026

A (–2, 0) and B(2, 0) are two fixed points and P is a point such that PA – PB = 2. Let S be the circle x 2 + y 2 = r 2

Column - I	Column - II
(i) If r = 2, then number of points P satisfying to PA – PB = 2 and lying on the circle S is	[A] 2
(ii) If r =1, then number of point P satisfying to circle S and PA – PB = 2 is	[B] 4
(iii) For r = 2, the number of common tangents is	[C] 0
(iv) For r = , the number of common tangents is	[D] 1

Correct Matrix Matching

Verified by Experts

The correct answer is:

(i) [A]; (ii) [D]; (iii) [C]; (iv) [A]

Ans.

(i) [A]

(ii) [D]

(iii) [C]

(iv) [A]

Sol.

(i) 2

(ii) 1

(iii) 0

(iv) 2

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